bill and amy want to ride their bikes from thier neighborhood to school which is 14.4 kilometers away. It takes Amy 40 minutes to arrive at school. Bill arrives 20 minutes after Amy. How much faster is Amy's average speed fro the entire trip?

The entire trip for Amy would take 40 minutes there, 40 minutes back, 80 minutes total. Bill would take 60 minutes there and 60 minutes back, 120 minutes total. 80/120= 8/12= 4/6= 2/3 Which is approximately 67%. Hope this helped.

To find out how much faster Amy's average speed is for the entire trip, we need to calculate both Bill's and Amy's average speeds.

First, let's calculate the average speed for Amy's 40-minute ride:
Average speed = Total distance ÷ Time taken
Since Amy traveled a distance of 14.4 kilometers in 40 minutes, her average speed can be calculated as:
Average speed = 14.4 km ÷ 40 min

Now, let's calculate Bill's average speed. We know that Bill arrived 20 minutes after Amy, so he rode for 40 minutes + 20 minutes = 60 minutes.
Average speed = Total distance ÷ Time taken
Since Bill also traveled a distance of 14.4 kilometers but took 60 minutes to do so, his average speed can be calculated as:
Average speed = 14.4 km ÷ 60 min

Now, we can compare the two average speeds and find out how much faster Amy's average speed is compared to Bill's average speed.
To do this, we can calculate the difference between their average speeds:
Difference = Amy's average speed - Bill's average speed

You can now substitute the values we calculated to find the difference in average speeds.