Ammonia is composed of H and N in a ratio of 9.33g N to 2.00g H. If 4.56g N combine completely with H to form ammonia, how many grams of ammonia would be formed? How do you calculate this?
9.33/atomic mass N = 9.33/14 = 0.666 mol N.
2.00/atomic mass H = 2.00/1 = 2 mol H.
ratio is NH3.
4.56g x (1 mol NH3/1 mol N) x (17g NH3/1 mol NH3) x (1 mol N/14 g N) = ? g NH3.
To calculate the number of grams of ammonia that would be formed when 4.56g of N combines completely with H, we need to determine the ratio of N to ammonia in the given information.
According to the information provided, ammonia is composed of H and N in a ratio of 9.33g N to 2.00g H. This means that for every 9.33 grams of nitrogen, there are 2.00 grams of hydrogen.
To find the mass of ammonia, we can use this ratio to calculate the amount of hydrogen required to react with the given amount of nitrogen.
Step 1: Calculate the amount of hydrogen (H) required:
We know that the ratio of hydrogen to nitrogen is 2.00:9.33. Therefore, the amount of hydrogen required should be (2.00/9.33) multiplied by the given mass of nitrogen.
Amount of H = (2.00/9.33) * 4.56g
= 0.430g
Step 2: Calculate the molar mass of NH3 (ammonia):
The molar mass of ammonia (NH3) can be calculated by adding the atomic masses of nitrogen (N) and hydrogen (H).
Molar mass of NH3 = atomic mass of N + (atomic mass of H * 3)
= 14.01 g/mol + (1.01 g/mol * 3)
= 17.03 g/mol
Step 3: Calculate the number of moles of ammonia formed:
To determine the number of moles of ammonia formed, divide the given mass of hydrogen by the molar mass of ammonia.
Number of moles of NH3 = mass of H / molar mass of NH3
= 0.430g / 17.03 g/mol
= 0.025 moles
Step 4: Calculate the mass of ammonia:
Finally, we can calculate the mass of ammonia by multiplying the number of moles of ammonia by its molar mass.
Mass of NH3 = number of moles of NH3 * molar mass of NH3
= 0.025 moles * 17.03 g/mol
= 0.425g
Therefore, when 4.56g of nitrogen reacts completely with hydrogen, approximately 0.425 grams of ammonia will be formed.