A flask containing 5.00ml of 3M hcl solution required 14.45 of 1.00M naoh for titration. How many moles of hcl are present in the solution? The density of 3M hcl is 1.05g/ml.
My calculation
0.005L x 3M = 0.015 moles
0.01445 x 1m = 0.01445 moles
Who helps me to solve it
See your post above.
To determine the number of moles of HCl present in the solution, you can use the concept of stoichiometry and the balanced chemical equation between HCl and NaOH. The equation is:
HCl + NaOH → NaCl + H2O
Based on the balanced equation, it shows that 1 mole of HCl reacts with 1 mole of NaOH. This means the number of moles of HCl is equal to the number of moles of NaOH used in the titration.
In your calculation, you correctly calculated the number of moles for the NaOH used in the titration, which is 0.01445 moles.
Therefore, the number of moles of HCl present in the solution is also 0.01445 moles.
By following these steps, you were able to solve for the number of moles of HCl in the solution.