math

How fast would a ball have to be thrown upward to reach a maximum height of 49 ft? [Hint: Use the discriminant of the equation
16t2 − v0t + h = 0.

  1. 👍
  2. 👎
  3. 👁
  1. This equation is derived from the following:

    at maximum height the velocity is zero.
    y(current height)= y0 (initial height)+v0t+.5at^2

    take the derivative

    32t-v0=0 so vo=32t

    Plug this in for the v0 value

    16t2 − (32t)t + h = 0

    h=49ft

    -16t^2+49=0

    Solve for t:
    16t^2=49
    4t=7
    t=7/4

    Plug in t and h to solve for v0

    16t2 − v0t + h = 0 where h=49 and t=7/4

    16(7/4)^2-v0 (7/4) +49=0

    :P

    1. 👍
    2. 👎
  2. How fast would a ball have to be thrown upward to reach a maximum height of 49 ft? [Hint: Use the discriminant of the equation 16t2 − v0t + h = 0.]

    1. 👍
    2. 👎

Respond to this Question

First Name

Your Response

Similar Questions

  1. science

    a ball is thrown straight upward and returns to the thrower's hand after 3.00s in the air. A second ball is thrown at an angle of 30.0 deg with the horizontal. At what speed must the second ball be thrown so that it reached the

  2. Math

    Please help ! 1.)a catapult launches a boulder with an upward velocity of 122 feet per second. the height of the boulder, h, in feet after t seconds is givin by the function h(t)=-16t^2+122t+10. what is the boulders maximum height

  3. Algebra 1

    A baseball is thrown into the air with an upward velocity of 30 ft/s. Its height h, in feet, after t seconds is given by the function h=-16t^2+6. How long will it take the ball to reach its maximum height? What is the ball's

  4. algebra

    A ball is thrown into the air with an upward velocity of 28 ft/s. Its height (h) in feet after t seconds is given by the function h = –16t² + 28t + 7. How long does it take the ball to reach its maximum height? What is the

  1. phy

    A blue ball is thrown upward with an initial speed of 20.6 m/s, from a height of 0.8 meters above the ground. 2.5 seconds after the blue ball is thrown, a red ball is thrown down with an initial speed of 8.2 m/s from a height of

  2. physics

    A ball is thrown upward at a speed v0 at an angle of 52.0˚ above the horizontal. It reaches a maximum height of 7.3 m. How high would this ball go if it were thrown straight upward at speed v0?

  3. pre-calc

    Physics: a ball is thrown vertically upward with an initial velocity of 80 feet per second. the distance (in feet) of the ball from the ground after t seconds if s=80t-16tt^2 a) draw the illustration b) for what time interval is

  4. math

    A ball is thrown into the air with an upward velocity of 20 ft/s. Its height (h) in feet after t seconds is given by the function h(t) = –16t^2 + 20t + 2. How long does it take the ball to reach its maximum height? What is the

  1. math

    A ball is thrown into the air with an upward velocity of 48 /. Its height ℎ in feet after seconds is given by the function ℎ = −162 + 48 + 9. How long does it take the ball to reach is the maximum height? What is the

  2. physics

    a ball is thrown at an initial angle of 37 and initail velocity of 23.0 m/s reaches a maximum height h, as shwon in the Figure. With what initial speed must a ball be thrown straight up to reach the same maximum height h?

  3. Math

    1. Graph the quadratic equation y = x2 + x – 2. Identify the axis of symmetry and the vertex. 2. A ball is thrown from the top of a 50-ft building with an upward velocity of 24 ft/s. When will it reach its maximum height? How

  4. Physics

    A red ball is thrown down with an initial speed of 1.3 m/s from a height of 28.0 meters above the ground. Then, 0.6 seconds after the red ball is thrown, a blue ball is thrown upward with an initial speed of 24.7 m/s, from a

You can view more similar questions or ask a new question.