A 28.6 g of iron ore is treated as follows. The
iron in the sample is all converted by a series
of chemical reactions to Fe2O3. The mass of
Fe2O3 is measured to be 10.1 grams. What
was the percent iron in the sample of ore?
Same song, fifth dance.
To find the percent of iron in the sample of ore, you need to calculate the mass of iron (Fe) in the sample and then divide it by the total mass of the sample. Here's how you can do it:
1. Calculate the mass of iron (Fe) in the sample:
Since all the iron in the sample is converted to Fe2O3, you can assume that the mass of iron (Fe) is equal to the mass of Fe2O3.
Mass of Fe = Mass of Fe2O3 = 10.1 grams
2. Now, calculate the percentage of iron (Fe) in the sample:
To find the percentage, divide the mass of iron (Fe) by the total mass of the sample and multiply by 100.
Percentage of iron = (Mass of Fe / Total mass of the sample) x 100
Total mass of the sample = 28.6 grams
Percentage of iron = (10.1 grams / 28.6 grams) x 100
Percentage of iron = 35.31%
Therefore, the percent of iron in the sample of ore is approximately 35.31%.