# Algebra2

Write an equation for the line in point/slope form and slope/intercept form that has the given condition.

Help?..

4. Slope = 3/2 and passes through the origin.

5. x-intercept = 4 and y-intercept = -3

6. Passes through (3, 2) and is parallel to 2x-y=4

7. Passes through (-1, -1) and is perpendicular to y= (5)/(2)x+3

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1. as you know, slope is ∆y/∆x
so, for any point (x,y) on the line containing (h,k) with slope m,

m = ∆y/∆x = (y-k)/(x-h)
or, as some like it,
y = m(x-h) + k

So, for #6,
2x-y = 4
y = 2x-4, so
slope is 2, so

(y-2) = 2(x-3)
y = 2x - 4

Do the others the same way. Com eon back if you get stuck. Be sure to show how you got there.

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posted by Steve

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