a very small ball has a mass of 5 x 10^-3 kg and a charge of 4x10^-6C(microC). What magnitude electric field directed upwad will balance the weight of the ball?
force electric=mg
Eq=mg
E=mg/q
1.2 x 10^4 N/C
To determine the magnitude of the electric field that will balance the weight of the ball, we need to understand the forces acting on the ball.
1. Weight force (gravitational force): The weight (W) of the ball is given by the product of its mass (m) and the acceleration due to gravity (g): W = m * g.
2. Electric force: The electric force (Fe) on a charged object in an electric field (E) is given by the product of the charge (q) and the electric field strength (E): Fe = q * E.
To balance the weight of the ball, the electric force must equal the weight force. Therefore, we can set up the following equation:
q * E = m * g
Plugging in the given values:
(4x10^-6 C) * E = (5x10^-3 kg) * (9.8 m/s^2)
Now, let's solve for E:
E = [(5x10^-3 kg) * (9.8 m/s^2)] / (4x10^-6 C)
E = 49 N/C
Therefore, the magnitude of the electric field directed upward that will balance the weight of the ball is 49 N/C.