3.21 g of calcium carbonate is dissolved into 250.0 mL of water to make a homogenous solution. What is the concentration os this solution?

I worked this problem for you below. I also told you that CaCO3 won't dissolve in water.

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To calculate the concentration of a solution, you need to know the amount of solute (in this case, calcium carbonate) and the volume of the solvent (in this case, water). The concentration is typically expressed in terms of moles per liter (mol/L) or a similar unit.

Step 1: Calculate the number of moles of calcium carbonate:
First, convert the mass of calcium carbonate to moles using its molar mass. The molar mass of calcium carbonate (CaCO3) is:
Ca: 40 g/mol
C: 12 g/mol
O: 16 g/mol (3 oxygen atoms)
Therefore, the molar mass of CaCO3 is 40 + 12 + (16 x 3) = 100 g/mol.

To convert grams to moles, divide the mass of calcium carbonate by its molar mass:
moles of CaCO3 = mass of CaCO3 / molar mass of CaCO3 = 3.21 g / 100 g/mol

Step 2: Convert the volume of water to liters:
The given volume of water is 250.0 mL. To convert it to liters, divide by 1000:
volume of water in liters = 250.0 mL / 1000 mL/L = 0.250 L

Step 3: Calculate the concentration:
The concentration (C) is defined as moles of solute per liter of solution, so divide the moles of calcium carbonate by the volume of water:
concentration (C) = moles of CaCO3 / volume of water in liters

Plug in the values:
C = (3.21 g / 100 g/mol) / 0.250 L

C = 12.84 mol/L (rounded to four significant figures)

Therefore, the concentration of this solution is approximately 12.84 mol/L.