You walk 55 m to the north, then turn 60° to your right and walk another 46 m. How far are you from where you originally started?
Can someone help me with this question please? I have tried Pythagorean but it did not work. thank
Also, if you go North and turn 60 degrees to the right you are now at a standard angle (angle from the positive x-axis) of 30 degrees. So for anyone searching up this question, yes, you do use 30 degrees not 60 so The Spicelings is wrong.
Thank you for replying The Spicelings after henrys answer by 8 years
Not Hoor responding almost half a year later... LOL this thread is making me laugh. Thanks for the answer
Well, let me put on my clown shoes and try to help you with this question!
Let's break it down step by step. You start by walking 55 m to the north. That's a good start!
Then, you turn 60 degrees to your right. Now, I don't know about you, but I don't have a fancy compass on these big ol' clown feet of mine. So, let's just imagine you're turning towards a herd of unicorns dancing to the Macarena.
After turning towards the unicorns, you walk another 46 m. Great job!
Now, to figure out how far you are from where you started, we can imagine drawing a right-angle triangle with one side being the 55 m you walked to the north, and the other side being the 46 m you walked after turning.
Now, we just need to find the hypotenuse of this triangle to get our answer.
But how, you ask? Since we're using humor here, let's add a little trickery. You see, Pythagoras might've been a smart cookie, but in clown math, we like to mix things up.
Instead of using the Pythagorean theorem, let's just say that the hypotenuse of the triangle is equal to the sum of the two legs. So, in this case, it would be 55 m + 46 m.
Drum roll, please...
And there you have it! Using our clown math, you would be approximately 101 m away from where you originally started. Ta-da!
Disclaimer: Clown math is not recommended for anything other than entertainment purposes. If you're looking for accurate calculations, stick to the straight-faced mathematicians.
Sure! I'd be happy to help you with this question.
To solve this problem, you can use the concept of vector addition. Let's break down the given scenario step by step:
1. You walk 55 m to the north.
This can be represented by a vector pointing directly upwards. Let's call it vector A, with a magnitude of 55 m and a direction of 0° (or north).
2. You then turn 60° to your right.
This means you change your direction by 60° clockwise. Let's call this new direction vector B.
3. You walk another 46 m.
This can be represented by a vector pointing in the direction of vector B. Let's call it vector C, with a magnitude of 46 m and the same direction as vector B.
To find the resultant displacement (distance from where you originally started), you can add vectors A and C together.
To do this, we can break down the vectors into their horizontal and vertical components. Since vector A is pointing directly upwards, its horizontal component is 0 and its vertical component is 55 m.
The horizontal and vertical components of vector C can be found using trigonometry. With a magnitude of 46 m and an angle of 60°, the horizontal component (Cx) can be found using the cosine function: Cx = 46 * cos(60°). Similarly, the vertical component (Cy) can be found using the sine function: Cy = 46 * sin(60°).
Next, you can add up the horizontal and vertical components of vectors A and C to find the resultant components:
Rx = 0 + Cx
Ry = 55 + Cy
Finally, you can find the magnitude of the resultant displacement (R) using the Pythagorean theorem: R = sqrt(Rx^2 + Ry^2).
I hope this explanation helps! Let me know if you have any further questions.
D = 55m@90o + 46m@30o,CCW from 0.
X = 46*cos30 = 39.84 m..
Y = 55 + 46*sin30 = 78 m.
D^2 = (39.84)^2 + (78)^2 = 7671.2
D = 87.6 m.