check answer please. An object is pulled with 3 forces: 1 at 20n to the right another at 40n to the right and the third at 30n to the left. The net force is 30n to right
I agree.
forces to the right = 20n + 40n = 60n
force to the left = 30n
I agree.
forces to the right = 20n + 40n = 60n
force to the left = 30n
net force = 60n - 30n or 30n
To check the answer, we need to find the net force by adding all the forces together.
Given forces:
Force 1: 20 N to the right
Force 2: 40 N to the right
Force 3: 30 N to the left
To find the net force, we can add the magnitudes of the forces and take into account their direction. Since the first two forces are in the same direction (to the right), we can simply sum them up:
20 N + 40 N = 60 N to the right
Now, we need to subtract the force that acts in the opposite direction (to the left):
60 N - 30 N = 30 N to the right
Based on the calculation, the net force is indeed 30 N to the right. Therefore, the answer is correct.
To check if the net force is indeed 30N to the right, we need to calculate the total force exerted on the object.
Given:
Force 1 (20N) to the right
Force 2 (40N) to the right
Force 3 (30N) to the left
To calculate the net force, we need to add up all the forces acting on the object:
Total force = Force 1 + Force 2 + Force 3
Total force = (20N to the right) + (40N to the right) + (30N to the left)
When we add these forces, we need to consider the direction. Forces in the same direction (right or left) can be added, while forces in opposite directions need to be subtracted.
Total force = (20N + 40N) - 30N
Total force = 60N - 30N
Total force = 30N to the right
Therefore, the net force acting on the object is indeed 30N to the right.