Write the net ionic equation for the reaction between sodium chloride and cobalt (ll) nitrate.
so far i have...
2NaCl(aq)+ Co(NO3)2(aq)---> NaNO3(aq)+CoCl2(s)
To write the net ionic equation, we need to first write the balanced chemical equation for the reaction.
The balanced chemical equation for the reaction between sodium chloride (NaCl) and cobalt (II) nitrate (Co(NO3)2) is:
2NaCl(aq) + Co(NO3)2(aq) → 2NaNO3(aq) + CoCl2(s)
Now, let's break the balanced equation into its ionic forms. Only the compounds that dissociate into ions in solution will be written as ions. The solid CoCl2 is not dissociated in solution, so it will not be written as ions.
2Na+(aq) + 2Cl-(aq) + Co2+(aq) + 2NO3-(aq) → 2Na+(aq) + 2NO3-(aq) + CoCl2(s)
Now, we can cancel out the ions that appear on both sides of the equation since they do not participate in the reaction. In this case, the Na+ and NO3- ions cancel out, leaving us with the net ionic equation:
2Cl-(aq) + Co2+(aq) → CoCl2(s)
Therefore, the net ionic equation for the reaction between sodium chloride and cobalt (II) nitrate is:
2Cl-(aq) + Co2+(aq) → CoCl2(s)