a baseball team has already played 37 games and won 21 games. The season has a total of 63 games. How many more games do they have to win to keepthe same winning percentage? (answer should be a whole number)
total played: 58
win pct = 21/58 = 36.2%
36.2% of 63 = 22.8
So, they need 23 wins by the end of the season. They need 2 more wins.
Your team has won 80% of their games. How many games was played if your team won
20 games?
To find out how many more games a baseball team needs to win to maintain the same winning percentage, we need to calculate the number of wins they should have after playing all 63 games.
First, we calculate the current winning percentage by dividing the number of wins (21) by the number of games played (37).
Current winning percentage = 21/37 = 0.567 (rounded to three decimal places)
Next, we want to find the number of games the team needs to win out of the remaining games (x) to maintain the same winning percentage.
So, we set up the following equation: (21 + x) / (37 + x) = 0.567
Now we solve for x:
Multiply both sides of the equation by (37 + x) to eliminate the denominator: (21 + x) = 0.567 * (37 + x)
Distribute 0.567: 21 + x = 21.009 + 0.567x
Subtract 0.567x from both sides: x - 0.567x = 21.009 - 21
Combine like terms: 0.433x = 0.009
Divide both sides by 0.433: x = 0.009 / 0.433
x ≈ 0.0207
Since we need to have a whole number of wins, we round up to the nearest whole number. So the team needs to win 1 more game to maintain the same winning percentage after playing all 63 games.