Physics

A 15 kg box sits on a horizontal force.

the coefficient of static fricition between the box and the surface is 0.70. if a force P is exerted on the box at an angle directed 37 degrees below the horizontal, what must be the magnitude of P to get the box moving??

asked by Teresa
  1. break up the force into a vertical (downward) and horizontal. The component downward adds to the force of friction.

    Forcefriction=(Psin37+15*9.8)*.70

    So Pcos37 must equal this force, solve for P.

    posted by bobpursley

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