What NaCl concentration results when 254 mL of an 0.880 M NaCl solution is mixed with 412 mL of a 0.450 M NaCl solution?
moles from 1 = M x L = ?
moles from 2 = M x L = ?
M of mixture = (total moles/total L) = ?
To find the final concentration of NaCl when the two solutions are mixed, we need to use the principle of conservation of mass.
1. Let's start by calculating the total amount of NaCl in the solution before mixing.
- In the first solution, we have 254 mL of a 0.880 M NaCl solution.
- For the second solution, we have 412 mL of a 0.450 M NaCl solution.
2. To find the total amount of NaCl in each solution, we multiply the volume (in liters) by the concentration (in moles per liter):
- For the first solution: 254 mL * (0.880 mol/L) = 223.52 mmol of NaCl
- For the second solution: 412 mL * (0.450 mol/L) = 185.4 mmol of NaCl
3. To calculate the total amount of NaCl in the final solution after mixing, we sum the amounts of NaCl from each solution:
- Total NaCl = 223.52 mmol + 185.4 mmol = 408.92 mmol
4. Now, let's calculate the total volume of the mixed solution by adding the volumes of the two solutions:
- Total volume = 254 mL + 412 mL = 666 mL
5. Finally, we can calculate the final concentration of NaCl in the mixed solution by dividing the total amount of NaCl (in moles) by the total volume (in liters):
- Final concentration = 408.92 mmol / 666 mL = 0.614 M (rounded to three decimal places)
Therefore, the NaCl concentration in the final mixed solution is approximately 0.614 M.