solve equation then check for extraneous solution please someone explain this to me.
6/6-4x/=8+4
then one that is solve the inequality
s/x+3/4<2
I don't understand these problems and then it says to graph
1. 6|6-4x| = 4+8 = 12.
Divide both sides by 6 to isolate bracket:
|6-4x| = 2
6-4x = +-2
-4x = +-2 - 6
-4x = 2-6 = -4
X = 1.
-4x = -2-6 = -8
X = 2.
Solution set: X = 1, and X = 2.
2. 5|x+3|4 < 2.
20|x+3| < 2
|x+3| < 2/20
|x+3| < 1/10
x+3 < 1/10
X < 1/10 - 30/10
X < -29/10.
-x-3 < 1/10
-x < 1/10 + 30/10
-x < 31/10
X > -31/10.
Solution set: < -29/10, and X > -31/10.