math

solve equation then check for extraneous solution please someone explain this to me.
6/6-4x/=8+4

then one that is solve the inequality
s/x+3/4<2

I don't understand these problems and then it says to graph



asked by kevin
  1. 1. 6|6-4x| = 4+8 = 12.
    Divide both sides by 6 to isolate bracket:
    |6-4x| = 2
    6-4x = +-2
    -4x = +-2 - 6
    -4x = 2-6 = -4
    X = 1.
    -4x = -2-6 = -8
    X = 2.

    Solution set: X = 1, and X = 2.

    2. 5|x+3|4 < 2.
    20|x+3| < 2
    |x+3| < 2/20
    |x+3| < 1/10
    x+3 < 1/10
    X < 1/10 - 30/10
    X < -29/10.

    -x-3 < 1/10
    -x < 1/10 + 30/10
    -x < 31/10
    X > -31/10.

    Solution set: < -29/10, and X > -31/10.






    posted by Henry

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