absolute value equation

2/3x-5/-8=8
Can someone help do not understand

2|3x-5|-8 = 8.

Isolate the bracket:
2|3x-5| = 8+8
2|3x-5| = 16
Divide both sides by 2:
|3x-5| = 8
The number whose|8| can be +- 8:
3x-5 = +-8
3x = +-8 + 5
3x = 8+5 =13
X = 13/3.

3x = -8 + 5 = -3
X = -1.

Solution set: X = -1, and X = 13/3.

Sure! I can help you solve the absolute value equation step-by-step.

First, let's simplify the equation by getting rid of the fractions. To do this, we can multiply every term by the least common denominator of 3 and 8, which is 24. This will eliminate the fractions.

So the equation becomes:

24*(2/3)x - 24*(-5)/(-8) = 24*8

Next, simplify each term of the equation:
16x + 15 = 192

Now, let's isolate the absolute value term. Subtract 15 from both sides of the equation:
16x = 192 - 15
16x = 177

To solve for x, we need to remove the coefficient of 16 from the variable. We can do this by dividing both sides of the equation by 16:
x = 177 / 16

The final step is to simplify the fractional answer, if possible. In this case, the answer is already simplified, so x = 177 / 16 is the solution to the absolute value equation.

I hope this helps! Let me know if you have any further questions.

Sure, I can help you solve the absolute value equation.

The equation you've given is:

(2/3)x - 5 / -8 = 8

To start solving this equation, we need to isolate the absolute value expression.

First, multiply both sides of the equation by -8 to eliminate the fraction:

-8 * [(2/3)x - 5 / -8] = -8 * 8

This simplifies to:

(-8 * 2/3)x + 40 = -64

Next, simplify the left side of the equation:

(-16/3)x + 40 = -64

To eliminate the fraction, we can multiply both sides of the equation by the reciprocal of -16/3, which is -3/16:

(-3/16) * [(-16/3)x + 40] = (-3/16) * (-64)

Simplifying further, we get:

x - (3/4)(40) = 12

x - 30 = 12

Now, isolate x by adding 30 to both sides of the equation:

x - 30 + 30 = 12 + 30

This simplifies to:

x = 42

So, the solution to the absolute value equation is x = 42.