# Math

An isosceles triangle has its vertex at the origin and the ends of its base on the parabola y=9-x^2. Express the area of the triangle as a function of the length of its base. Assume its base lies above the x-axis.

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1. a = 1/2 bh

Assuming the base of the triangle is parallel to the x-axis, then

a = 1/2 b (9 - b/2)^2

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posted by Steve

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