An aqueus solution of sodium mitrate(NaNO3) contains 0.85 grams of sodium nitrate and its concentration is 0.1mol L^-1. What is the volume. in millilitres, of the sodium nitrate solution?
mols NaNO3 = grams/molar mass
Then M = mols/L. You know M and mols, solve for L and convert to mL.
To find the volume of the sodium nitrate solution, we can use the formula:
Concentration (mol/L) = Amount of solute (mol) / Volume of solution (L)
Given:
Concentration = 0.1 mol/L
Amount of solute = 0.85 g
First, we need to convert the amount of solute from grams to moles. To do this, we need to know the molar mass of sodium nitrate (NaNO3).
Molar mass of NaNO3 = 22.99 g/mol (sodium) + 14.01 g/mol (nitrogen) + 3 * 16.00 g/mol (oxygen)
= 85.00 g/mol
Now, we can calculate the number of moles using the formula:
Amount of solute (mol) = Mass of solute (g) / Molar mass (g/mol)
Amount of solute = 0.85 g / 85.00 g/mol
= 0.01 mol
Now that we have the amount of solute in moles, we can rearrange the formula to find the volume of the solution:
Volume of solution (L) = Amount of solute (mol) / Concentration (mol/L)
Volume of solution = 0.01 mol / 0.1 mol/L
= 0.1 L
Finally, we can convert the volume from liters to milliliters:
Volume of solution (mL) = Volume of solution (L) * 1000 mL/L
= 0.1 L * 1000 mL/L
= 100 mL
Therefore, the volume of the sodium nitrate solution is 100 milliliters.