physics

A golf ball is thrown at an angle of 37 degree with horizontal with initial speed of 50 m/s. what is the maximum horizontal distance???

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  1. L=vₒ²sin2α/g=50²•sin74º/9.8=245.2 m

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  2. this question is multiple choice there are choices and this answer is not among them :(

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  3. Upward motion (from the start point to the highest point)
    v=v(0y)-gt ,
    v=0
    t= v(0y)/g=v(0) •sinα/g
    the horizontal range is
    L=2•v(x) •t=2•v(0) •cosα•v(0) •sinα/g= =v²(0) •sin2 α/g.
    This is correct answer (both formula and calculation).
    Show your set of answers.

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