A bullet is fired through a wall that is 10.0 cm. thick. The bullet entered the wall at 400. m/s, and it exited from the wall at 220. m/s. What was the average acceleration of the bullet while it was passing through the wall?
a=(v1²-v2²)2d= (440²-220²)/0.2= …
a=(V2^2-V1^2)/2d
To find the average acceleration of the bullet while passing through the wall, we need to calculate the change in velocity and the time it took for the bullet to pass through the wall.
First, let's find the change in velocity:
Change in velocity (Δv) = Final velocity (v_f) - Initial velocity (v_i)
Δv = 220 m/s - 400 m/s
Δv = -180 m/s
Note: The negative sign indicates that there was a decrease in velocity.
Next, we need to determine the time it took for the bullet to pass through the wall. Since we have the thickness of the wall given, we can assume that the bullet traveled a distance of 10.0 cm.
Now, we can calculate the time it took (t) for the bullet to travel through the wall using the average velocity formula:
Average velocity (v_avg) = Distance (d) / Time (t)
v_avg = 10.0 cm / t
t = 10.0 cm / v_avg
But we need to convert the thickness of the wall to meters since the velocities are given in m/s:
d = 10.0 cm = 0.1 m
Now, we can rearrange the average velocity formula to calculate Time (t):
t = d / v_avg
t = 0.1 m / v_avg
Since average velocity is defined as the change in displacement divided by the change in time, we can substitute Δv for v_avg in the above equation:
t = 0.1 m / Δv
t = 0.1 m / (-180 m/s)
t ≈ -0.000556 s (rounded to 6 significant figures)
Note: The negative sign indicates that the time is negative, which does not make physical sense. The negative time suggests an error in the calculation or the assumption made.
Since time cannot be negative, we can conclude that there is an error either in the data or the given problem statement. Please double-check the values or the question provided to ensure accuracy.