Tonya and Lauren are designing a soccer uniform.they want to use two colors on the shirt.thier choices are green,orange,yellow,purple,blue,and silver.how many ways can they choose two colors.

since there are 6 colors,

there are 6 ways to choose the first color.
For each of those choices there are only 5 ways to choose the other color.

So, 6*5 = 30 ways to choose the colors.

However, if the order does not matter (for example if blue and orange is considered the same as orange and blue), then there are only 30/2 = 15 ways to choose.

thank you you are a great help!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

30 way

30 is the answer lol cheats

Without replacement it is 15 combination

I don't really get it. If there are 15 combinations isn't it supposed to be like: green orange bla blah blah or something like that and also I have been using you answers to help me with Ms.Skillerns homework because we are on 3.6 and I still don't. Thank you for telling me the answers. Bye

I got about 5 for each what did I do wrong

I have no idea o-o

How do we the ways they can choose to colors

To find out how many ways Tonya and Lauren can choose two colors from the given options, we can use the concept of combinations.

The formula to calculate combinations is:

C(n, r) = n! / (r! * (n - r)!)

where n represents the total number of options and r represents the number of choices.

In this case, there are 6 colors available (green, orange, yellow, purple, blue, and silver), and they want to choose 2 colors.

Using the formula, we can substitute the values:

C(6, 2) = 6! / (2! * (6 - 2)!)

Calculating further:

C(6, 2) = 6! / (2! * 4!)

To simplify this expression, let's expand the factorials:

C(6, 2) = (6 * 5 * 4!)/(2! * 4!)

The 4! terms in the numerator and denominator cancel out:

C(6, 2) = (6 * 5)/(2 * 1)

C(6, 2) = 30/2

C(6, 2) = 15

Therefore, there are 15 different ways Tonya and Lauren can choose two colors for their soccer uniform.