A major league pitcher can throw a baseball at about 45 m/s (about 100mph). If a baseball has a mass of .55kg how large is the impulse provided by the catchers mitt when he catches the ball.

To find the impulse provided by the catcher's mitt when he catches the ball, we need to use the concept of impulse.

Impulse is defined as the change in momentum of an object and is calculated using the formula:

Impulse = Force × Time

To determine the impulse, we need to know the initial momentum of the baseball and the time taken to stop it.

To find the initial momentum, we can use the formula:

Momentum = Mass × Velocity

Given that the mass of the baseball is 0.55 kg and the velocity is 45 m/s, we can calculate the initial momentum:

Momentum = 0.55 kg × 45 m/s = 24.75 kg·m/s

Next, we need to determine the time taken to stop the baseball. Since we don't have this information directly, we can approximate it by considering the process of catching a baseball.

Assuming that the time taken to stop the ball is about 0.01 seconds, we can use this value to calculate the impulse.

Impulse = Force × Time

Since the direction of the force and the time is the same, we can use the impulse formula to find the force using the momentum:

Force = Impulse ÷ Time

Plugging in the values, we have:

Force = 24.75 kg·m/s ÷ 0.01 s = 2475 N

Therefore, the impulse provided by the catcher's mitt when he catches the ball is 2475 N.