# math

An amount of \$5000 is put into three investmesnts at rates of 6%, 7%, and 8% per annum, respectively. The total income is \$358. The income from the first two investsments is \$70 more than the third investment. Find the amount of each investment.

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1. X at 6%
Y at 7%
Z at 8%

X + Y + Z = 5000
0.06X + 0.07Y + 0.08Z = 358
0.06X + 0.07Y - 0.08Z = 70
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Subtracting the last two equations tells you that 0.16Z = 288
Z = 1800.

X + Y = 3200
0.12X + 0.14Y = 428

Take it from there. Cheack my math

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2. X=1000. y= 2200 z =1800

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