Consider the reduction of 4-t-butylcyclohexanone.
If the procedure calls for 153 mg of 4-t-butylcyclohexanone, what mass of sodium borohydride should be added?
Well, if we're talking about reducing 4-t-butylcyclohexanone, I guess it's time to bring out the humor hammer because this question needs a little punchline to lighten the mood. So, here it goes!
Why did the sodium borohydride go to the comedy club?
Because it wanted to add a little 'reduction' to its routine! 😄🎭
Now, to answer your question, to determine the mass of sodium borohydride needed, we need to look at the stoichiometry of the reaction. Since we don't have enough information about the molar ratios involved in the reaction, it's challenging for me to provide an accurate answer. However, it is essential to consult a trusted source, such as a lab manual or an expert in the field, to determine the appropriate amount of sodium borohydride required for the reduction. Safety first, folks! Good luck with your experiment!
To determine the mass of sodium borohydride (NaBH4) needed for the reduction of 4-t-butylcyclohexanone, we need the stoichiometric ratio between the two compounds. The balanced chemical equation for the reduction reaction is as follows:
4-t-butylcyclohexanone + NaBH4 → 4-t-butylcyclohexanol + NaB(OH)4
From the stoichiometry, we know that one mole of 4-t-butylcyclohexanone reacts with one mole of NaBH4. We can use this information along with the molar mass of 4-t-butylcyclohexanone to calculate the amount of NaBH4 needed.
The molar mass of 4-t-butylcyclohexanone (C14H24O) can be calculated as follows:
C (14 * 12.01 g/mol) + H (24 * 1.01 g/mol) + O (1 * 16.00 g/mol) = 208.34 g/mol
Now, we can apply the concept of stoichiometry to determine the mass of NaBH4 needed.
1 mole of 4-t-butylcyclohexanone = 208.34 g
153 mg (0.153 g) of 4-t-butylcyclohexanone = (0.153 g / 208.34 g/mol) moles of 4-t-butylcyclohexanone
Since the stoichiometric ratio between 4-t-butylcyclohexanone and NaBH4 is 1:1, the moles of NaBH4 needed will be the same as the moles of 4-t-butylcyclohexanone.
Therefore, the mass of NaBH4 needed is:
0.153 g of NaBH4.
To determine the mass of sodium borohydride required for the reduction of 4-t-butylcyclohexanone, you need to consider the stoichiometry of the reaction. The balanced equation for the reduction of 4-t-butylcyclohexanone with sodium borohydride is:
4-t-butylcyclohexanone + 4 NaBH4 + 4 H2O → 4-t-butylcyclohexanol + 4 NaOH + 4 B(OH)3
From the balanced equation, you can see that the molar ratio between 4-t-butylcyclohexanone and sodium borohydride is 1:4. This means that for every one mole of 4-t-butylcyclohexanone, you need four moles of sodium borohydride.
To calculate the mass of sodium borohydride needed, you can follow these steps:
Step 1: Convert the given mass of 4-t-butylcyclohexanone to moles.
molar mass of 4-t-butylcyclohexanone = 4(12.01 g/mol) + 14.03 g/mol + 10(1.01 g/mol) + 16.04 g/mol = 166.27 g/mol
moles of 4-t-butylcyclohexanone = 153 mg / 166.27 g/mol
= 0.9205 mmol
Step 2: Use the mole ratio to determine the moles of sodium borohydride required.
Since the mole ratio between 4-t-butylcyclohexanone and sodium borohydride is 1:4,
moles of sodium borohydride = 4 * moles of 4-t-butylcyclohexanone
= 4 * 0.9205 mmol
= 3.682 mmol
Step 3: Convert moles of sodium borohydride to mass.
molar mass of sodium borohydride = 22.99 g/mol + 1.01 g/mol + 4(1.01 g/mol) = 37.83 g/mol
mass of sodium borohydride = moles of sodium borohydride * molar mass of sodium borohydride
= 3.682 mmol * 37.83 g/mol
= 139.23 mg
Therefore, you should add approximately 139.23 mg of sodium borohydride for the reduction of 153 mg of 4-t-butylcyclohexanone.
If you know the equation, this becomes a general chemistry stoichiometry problem.
1. Write the equation. You need only mols of ketone to mols borohydride.
2. Convert 153 mg of the ketone to mols. mols = grams/molar mass
3. Convert mols ketone to mols of the borohydride using the equation coeficients.
4. Convert mols borohydride to grams. g = mols x molar mass.