If a circle with center O has equilateral triangle AOB inscribed with sides 10 inches long. If OC is perpendicular to AB at P, what is the length of AP in inches?
To find the length of AP, we can use the properties of an equilateral triangle inscribed in a circle.
In an equilateral triangle, the altitude from any vertex bisects the opposite side. This means that AP is half the length of AB.
Given that AB is 10 inches, we can conclude that the length of AP is 10 inches divided by 2, which equals 5 inches.
Therefore, the length of AP is 5 inches.