One day we decided to dive from town A to town B. In order to get there we had to drive through town B and then town C. it is 10 miles farther from town A to town B then it is to town B to C. It is 10 miles farther from town B to town C than it is from town C to town D. It is 330milesfrom town A to town D . how far is it from town A to town B?
I think you have a typo and meant to say "One day we decided to dive from town A to town D" , or else why would you drive from A to B and then to C to get from A to B.
I also assume that the town are along the same road.
Let BC = x
then AB = x+10
CD = x-10
x+10 + x + x-10 = 330
3x = 330
x =110
AB = 120
120
To solve this problem, let's break down the given information and work through the steps.
1. It is 10 miles farther from town A to town B than it is from town B to town C.
2. It is 10 miles farther from town B to town C than it is from town C to town D.
3. It is 330 miles from town A to town D.
Let's assign variables to represent the distances:
Let x = distance from town B to town C
Then, the distance from town A to town B is x + 10 (since it is 10 miles farther).
Now, let's calculate the distance from town C to town D using the given information:
From town B to town C is x miles.
Therefore, from town C to town D, the distance is x + 10 miles (since it is 10 miles farther).
Now, we can express the total distance from town A to town D using the variables:
Distance from A to D = Distance from A to B + Distance from B to C + Distance from C to D
330 = (x + 10) + x + (x + 10)
330 = 3x + 30
Now, let's solve for x:
3x + 30 = 330
3x = 330 - 30
3x = 300
x = 100
Now that we know x, we can find the distance from town A to town B:
Distance from A to B = x + 10 = 100 + 10 = 110
Therefore, the distance from town A to town B is 110 miles.