billy drops a watermelon from the top of three story building, 10m above the sidewalk. how fast is the watermelon going
WHEN?
When it hits the ground?
V = sqrt(2gH)
where h is the height and g is the acceleration of gravity.
To determine the speed at which the watermelon is going when it hits the ground, we can use the principles of physics. The initial velocity of the watermelon is zero (since it is dropped from rest) and the distance it falls is 10 meters. We can use the equation of motion, which relates distance, initial velocity, time, and acceleration, to solve for the final velocity.
The equation we can use is:
v^2 = u^2 + 2as
Where:
v = final velocity
u = initial velocity
a = acceleration
s = distance
Since the watermelon is falling under the influence of gravity, we can assume the acceleration is equal to the acceleration due to gravity, which is approximately 9.8 m/s^2 (assuming no air resistance).
Plugging in the given values, we have:
v^2 = 0^2 + 2 * 9.8 * 10
Simplifying further:
v^2 = 196
Taking the square root of both sides, we find:
v ≈ 14 m/s
Therefore, the watermelon is falling at a speed of approximately 14 meters per second when it hits the ground.