Suppose J is between H and K. Use the Segment Addition Postulate to solve for x. Then find the length of each segment.

HJ=2x+5
JK=3x-7
KH=18

2x + 5 + 3x - 7 = 18

5x - 2 = 18

5x = 20

x = 4

To find x using the Segment Addition Postulate, we need to set up an equation using the given information.

According to the Segment Addition Postulate, the sum of the lengths of HJ and JK is equal to the length of KH.

HJ + JK = KH

Substituting the expressions for HJ and JK, we have:

(2x + 5) + (3x - 7) = 18

Now, we can solve this equation for x:

2x + 5 + 3x - 7 = 18
5x - 2 = 18
5x = 20
x = 4

To find the length of each segment, we can substitute the value of x back into the expressions for HJ and JK:

HJ = 2x + 5 = 2(4) + 5 = 8 + 5 = 13
JK = 3x - 7 = 3(4) - 7 = 12 - 7 = 5
KH = 18

Therefore, the length of HJ is 13, JK is 5, and KH is 18 units.

HJ=2x +5

If J is between H and K where HJ = 2x + 5,

JK = 3x –7, and KH = 18, then x = 30.

true or flase

true

Given x is the midpoint of yz. given xy =6x+4 and yz=40, fing the value of x