a water tower holds 1 million gallons at 38 ft. what is the percent of the water in the tank when the level reaches 26 ft?
26/38 = 0.6842 = 68.42%
To find the percentage of water in the tank when the level reaches 26 ft, we need to calculate the volume of water at that height and compare it to the total volume of the tank.
First, let's determine the volume of water at 26 ft. We can use the concept of similar triangles to find this value.
Since we know the height of the water at 38 ft and its corresponding volume of 1 million gallons, we can set up the following proportion:
(volume at 26 ft) / (volume at 38 ft) = (height at 26 ft) / (height at 38 ft)
Let's solve for the volume at 26 ft.
(volume at 26 ft) / 1 million gallons = 26 ft / 38 ft
(volume at 26 ft) = (1 million gallons) * (26 ft / 38 ft)
Now we can calculate the volume at 26 ft using this proportion:
(volume at 26 ft) = (1 million gallons) * (26 / 38) = (1 million gallons) * 0.6842
(volume at 26 ft) ≈ 684,200 gallons
Now we can calculate the percentage of water in the tank at 26 ft by dividing the volume at 26 ft by the total volume of the tank (1 million gallons) and multiplying by 100:
(percentage) = [(volume at 26 ft) / (total volume)] * 100
(percentage) = [684,200 gallons / 1 million gallons] * 100
(percentage) = 68.42%
Therefore, when the water level reaches 26 ft, the tank will be approximately 68.42% full.