# Algebra

Find k, given that (2,k) is equidistant from (3,7) and (9,1).

How do I solve this problem?

1. 👍 4
2. 👎 1
3. 👁 1,005
1. The slope of the line segment joining (3,7) and (9,1) is -6/6 = -1.

Any point equidistant from those two points will lie on the perpendicular bisector of that line segment.

So, we want the line with slope=1, through (6,4), the midpoint of the segment.

y-4 = 1(x-6)
Now, we plug in (2,k) to get
k-4 = 2-6
k = 0

1. 👍 2
2. 👎 3

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