The foot of a ladder is placed 6 feet from a wall. If the top of the ladder is 8 feet up on the wall, how long is the ladder?
Okay i think i got it.
a^2 + b^2 = c^2
6^2 + 8^2 = c^2
36 + 64 = c^2
sqrt of 100 = sqrt of c^2
10ft = C
Is that right?
To find the length of the ladder, you can use the Pythagorean theorem, which states that in a right triangle, the square of the length of the hypotenuse (the longest side) is equal to the sum of the squares of the other two sides.
In this case, the ladder forms a right triangle with the wall. The distance from the foot of the ladder to the wall is one side, and the length of the ladder itself is the hypotenuse. The height of the ladder (the other side of the triangle) is given as 8 feet.
Let's denote the length of the ladder as 'x'. According to the Pythagorean theorem, we have:
x^2 = 6^2 + 8^2
Simplifying this equation, we get:
x^2 = 36 + 64
x^2 = 100
To solve for 'x', we take the square root of both sides:
x = √100
x = 10
Therefore, the length of the ladder is 10 feet.
Think about the Pythagorean theorem. The ladder length is the hypotenuse.
yep
a^2 + b^2 = c^2
c is the hypotenuse and a and b are the perpendicular sides of a right triangle