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Trigonometry
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Let y represent theta Prove: 1 + 1/tan^2y = 1/sin^2y My Answer: LS: = 1 + 1/tan^2y = (sin^2y + cos^2y) + 1 /(sin^2y/cos^2y) = (sin^2y + cos^2y) + 1 x (cos^2y/sin^2y) = (sin^2y + cos^2y) + (sin^2y + cos^2y) (cos^2y/sin^2y) =
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r=4sin9(thetha) How would I find values for this graph do I do 4*Sin 9 *a degree or 4 *sin (9* a degree) I don't understand
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math graphing
r=4sin9(thetha) How would I find values for this graph do I do 4*Sin 9 *a degree or 4 *sin (9* a degree) I don't understand
asked by jared on April 28, 2009
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