Lime, CaO, is produced by the decomposition reaction CaCO3(s) ® CaO(s) + CO2(g). What weight of CO2 is obtained by the decomposition of 38.7 g of CaCO3?
To calculate the weight of CO2 produced by the decomposition of 38.7 g of CaCO3, we need to use the stoichiometric ratio between CaCO3 and CO2.
The balanced equation for the decomposition of CaCO3 is:
CaCO3(s) -> CaO(s) + CO2(g)
From the equation, we can see that for every 1 mole of CaCO3 decomposed, 1 mole of CO2 is produced.
Now, let's calculate the number of moles of CaCO3:
Molar mass of CaCO3 = 40.08 g/mol (Ca) + 12.01 g/mol (C) + (3 x 16.00 g/mol) (3 O) = 100.09 g/mol
Number of moles of CaCO3 = mass / molar mass = 38.7 g / 100.09 g/mol ≈ 0.386 mol
Since the stoichiometric ratio is 1:1 between CaCO3 and CO2, the number of moles of CO2 produced is also 0.386 mol.
Now, let's calculate the weight of CO2:
Molar mass of CO2 = 12.01 g/mol (C) + (2 x 16.00 g/mol) (2 O) = 44.01 g/mol
Weight of CO2 = number of moles x molar mass = 0.386 mol x 44.01 g/mol ≈ 17.02 g
Therefore, the weight of CO2 obtained by the decomposition of 38.7 g of CaCO3 is approximately 17.02 g.
To find the weight of CO2 produced by the decomposition of 38.7 g of CaCO3, you need to use stoichiometry. Stoichiometry allows us to relate the amounts of reactants and products in a chemical reaction.
First, let's write down the balanced chemical equation for the reaction:
CaCO3(s) -> CaO(s) + CO2(g)
From the equation, we can see that 1 mole of CaCO3 produces 1 mole of CO2. We need to convert the given mass of CaCO3 to moles, and then use the mole ratio to determine the moles of CO2 produced. Finally, we can convert moles of CO2 to grams.
Here's how to calculate it step by step:
Step 1: Determine the molar mass of CaCO3
The molar mass of CaCO3 is calculated by adding up the atomic masses of calcium (Ca), carbon (C), and three oxygens (O).
Ca: 1 atom x 40.08 g/mol = 40.08 g/mol
C: 1 atom x 12.01 g/mol = 12.01 g/mol
O: 3 atoms x 16.00 g/mol = 48.00 g/mol
Total molar mass of CaCO3 = 40.08 g/mol + 12.01 g/mol + 48.00 g/mol = 100.09 g/mol
Step 2: Convert mass to moles
To convert grams of CaCO3 to moles, divide the given mass by the molar mass.
Moles of CaCO3 = 38.7 g / 100.09 g/mol = 0.386 moles
Step 3: Use the mole ratio
Since the balanced equation tells us that 1 mole of CaCO3 produces 1 mole of CO2, we can conclude that 0.386 moles of CaCO3 will produce 0.386 moles of CO2.
Step 4: Convert moles to grams
Finally, we can convert moles of CO2 to grams using the molar mass of CO2.
The molar mass of CO2 is calculated by adding up the atomic masses of carbon (C) and two oxygens (O).
C: 1 atom x 12.01 g/mol = 12.01 g/mol
O: 2 atoms x 16.00 g/mol = 32.00 g/mol
Total molar mass of CO2 = 12.01 g/mol + 32.00 g/mol = 44.01 g/mol
Weight of CO2 = Moles of CO2 x Molar mass of CO2
Weight of CO2 = 0.386 moles x 44.01 g/mol = 16.98 grams
Therefore, the weight of CO2 obtained by the decomposition of 38.7 g of CaCO3 is 16.98 grams.
mols CaCO3 = grams/molar mass.
Convert mols CaCO3 to mols CO2 using the coefficients in the balanced equation.
Now convert mols CO2 to grams. g = mols x molar mass.