If n!/2=(n-2)! then n=?

n(n-1)(n-2)!/2 = (n-2)!

n(n-1)/2 = 1
n(n-1) = 2
n^2 - n - 2 = 0
(n-2)(n+1) = 0
n = 2

check: 2!/2 = 0!
2/2 = 1

Seems they could have come up with a better problem for using this concept.