A distant galaxy is simultaneously rotating and receding from the earth. As the drawing shows, the galactic center is receding from the earth at a relative speed of uG = 1.7 x 106 m/s
Is there a question here?
To find the rotational speed of the distant galaxy, we need to calculate the net velocity. The net velocity is the vector sum of the rotational velocity and the recession velocity.
Given:
Recession velocity (uG) = 1.7 x 10^6 m/s
Let's assume the rotational velocity of the galaxy is represented by uR in meters per second.
The net velocity (uNet) can be calculated using the Pythagorean theorem:
uNet = √(uR^2 + uG^2)
Solving for uNet, we get:
uNet = √(uR^2 + (1.7 x 10^6)^2)
Since we have the value of uNet, which is the net velocity, we can now rearrange the equation to solve for uR:
uR = √(uNet^2 - (1.7 x 10^6)^2)
Substituting the given value of uG = 1.7 x 10^6 m/s, we can calculate uR:
uR = √(uNet^2 - (1.7 x 10^6)^2)
Please provide the value of uNet or any additional information to proceed with the calculation.