Calculus - Verification

Hello, I just wanted to verify this definite integral and if my answer is good:

a = 1 and b = 4
integral of

(1 - 1/x^2)(x^2 + 1/x) dx

= (x + 1/x)(x^3/3 + lnx) + C

(4 + 1/4)(64/3 + ln4) - (1 + 1)(1/3 + ln1)

= 96.56 - 0.6666 = 95.89

THank you

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  1. I do not think so. Multiply out and integrate each term.

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  2. (x^2 -1 + 1/x -1/x^3)dx

    x^2 dx - dx + dx/x - dx/x^3

    x^3/3 etc

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  3. integral a b dx is not integral a dx * integral b dx

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