A volume of 100mL of a 0.800 M HNO3 solution is titrated with 0.640 M KOH. Calculate the volume of KOH required to reach the equivalence point.
HNO3 + KOH ==> KNO3 + H2O
How many moles do you have? That's M x L HNO3. Look at the coefficients in the balanced equation. 1 mol HNO3 = 1 mol KOH; therefore, mols HNO3 = moles KOH.
M KOH = moles KOH/L KOH. You know M KOH and mols KOH; solve for L KOH.
To calculate the volume of KOH required to reach the equivalence point in the titration, we need to determine the balanced chemical equation for the reaction between HNO3 and KOH.
The balanced chemical equation for this reaction is:
HNO3 + KOH -> KNO3 + H2O
Based on the ratio of moles in the balanced equation, we know that one mole of HNO3 reacts with one mole of KOH to produce one mole of water (H2O).
Given the molarity and volume of the HNO3 solution, we can calculate the number of moles of HNO3 present:
moles of HNO3 = Molarity * Volume
= 0.800 M * 0.100 L
= 0.080 mol
Since the stoichiometry of the balanced equation is 1:1 between HNO3 and KOH, the number of moles of KOH required to react with the HNO3 is also 0.080 mol.
Now, to determine the volume of KOH solution needed, we can use the molarity of KOH:
moles of KOH = Molarity * Volume
0.080 mol = 0.640 M * Volume
Volume = 0.080 mol / 0.640 M
Volume = 0.125 L = 125 mL
Therefore, the volume of KOH solution required to reach the equivalence point is 125 mL.
To calculate the volume of KOH required to reach the equivalence point, we need to find out the moles of HNO3 and KOH involved in the reaction.
1. Start by using the formula:
Molarity (M) = Moles (mol) / Volume (L)
2. Convert the given volume of HNO3 solution from milliliters (mL) to liters (L).
100 mL = 100 mL * (1 L / 1000 mL) = 0.1 L
3. Use the given molarity of HNO3 solution to calculate the moles of HNO3.
Moles of HNO3 = Molarity of HNO3 * Volume of HNO3 solution
= 0.800 mol/L * 0.1 L
= 0.080 mol
4. According to the balanced chemical equation between HNO3 and KOH, the stoichiometry is 1:1. This means that 1 mole of HNO3 reacts with 1 mole of KOH.
5. Since the volume and molarity of KOH are unknown, let's denote them as V(KOH) and M(KOH), respectively.
6. Using the mole ratio from the balanced equation, we can set up the equation:
Moles of HNO3 = Moles of KOH
0.080 mol = M(KOH) * V(KOH)
7. Given the molarity of KOH as 0.640 M, we can rearrange the equation to solve for V(KOH):
V(KOH) = Moles of HNO3 / M(KOH)
= 0.080 mol / 0.640 mol/L
= 0.125 L
8. Finally, convert the volume from liters to milliliters:
V(KOH) = 0.125 L * (1000 mL / 1 L)
= 125 mL
Therefore, the volume of KOH required to reach the equivalence point is 125 mL.