Finde the mean , variance , standard deviation

N-127, P=0.66

To find the mean, variance, and standard deviation, we need to know the probability of success (P) and the number of trials (N) in a binomial distribution.

Mean (μ):
The mean, denoted as μ, can be calculated using the formula μ = N * P. In this case, N = 127 and P = 0.66, so the mean is μ = 127 * 0.66 = 83.82.

Variance (σ^2):
The variance, denoted as σ^2, can be calculated using the formula σ^2 = N * P * (1 - P). In this case, N = 127 and P = 0.66, so the variance is σ^2 = 127 * 0.66 * (1 - 0.66) = 27.5636.

Standard Deviation (σ):
The standard deviation, denoted as σ, can be calculated by taking the square root of the variance. So, in this case, the standard deviation is σ = sqrt(27.5636) = 5.25 (rounded to two decimal places).

Therefore, the mean is 83.82, the variance is 27.5636, and the standard deviation is 5.25.