Two pellets, each with a charge of 1.0 microcoulomb (1.0×10−6 ), are located 4.0 (4.0×10−2 ) apart.A)find the electric force between them B)What would be the mass of an object that would experience this same force in Earth's gravitational field?

5.6 N

F = k q^2/r^2

= 9x10^9*1x10^-12/16x10^-4
= 5.6 N

5.6=m*9.8 => m=5.6/9.8=5.7 Kg

A) To find the electric force between two charges, we can use Coulomb's law:

Electric force (F) = (k * |q1 * q2|) / r^2

Where:
- k is the electrostatic constant (k = 8.99 × 10^9 Nm^2/C^2),
- q1 and q2 are the charges (in this case, 1.0 microcoulomb = 1.0 × 10^-6 C),
- r is the distance between the charges (in this case, 4.0 cm = 4.0 × 10^-2 m).

Plugging the values into the formula, we have:

F = (8.99 × 10^9 Nm^2/C^2) * (|1.0 × 10^-6 C * 1.0 × 10^-6 C|) / (4.0 × 10^-2 m)^2

Calculating this gives:

F = 0.4495 N

Therefore, the electric force between the two charges is 0.4495 Newtons.

B) To find the mass of an object that experiences the same force as the electric force in Earth's gravitational field, we need to equate the electric force to the gravitational force.

Gravitational force (Fg) = m * g

Where:
- m is the mass of the object,
- g is the acceleration due to gravity (9.8 m/s^2).

Setting the gravitational force equal to the electric force:

Fg = F = 0.4495 N
m * g = 0.4495 N

Solving for m, we have:

m = Fg / g
m = 0.4495 N / 9.8 m/s^2

Calculating this gives:

m = 0.04594 kg

Therefore, the mass of an object that would experience the same force as the electric force between the charges in Earth's gravitational field is approximately 0.04594 kilograms.

A) To find the electric force between the two pellets, you can use Coulomb's Law, which states that the electric force between two charges is directly proportional to the product of the charges and inversely proportional to the square of the distance between them.

Coulomb's Law equation is given by:

F = (k * |q₁ * q₂|) / r²

where:
F is the electric force,
k is the electrostatic constant (8.99 x 10^9 Nm²/C²),
|q₁| and |q₂| are the magnitudes of the charges, and
r is the distance between the centers of the charges.

Given that the charges of both pellets are 1.0 microcoulomb (1.0×10^⁻6 C) and the distance between them is 4.0 (4.0×10^⁻2 m), we can substitute these values into the equation:

F = (8.99 × 10^9 Nm²/C²) * |(1.0 × 10^⁻6 C) * (1.0 × 10^⁻6 C)| / (4.0 × 10^⁻2 m)²

Simplifying this equation will give you the electric force between the two pellets.

B) To find the mass of an object that would experience this same force in Earth's gravitational field, we can use Newton's Second Law of Motion, which states that the force acting on an object is equal to the mass of the object multiplied by its acceleration.

In this case, the force acting on the object due to gravity is equal to the electric force calculated in part A. We can equate these two forces:

F_gravity = F_electric

mg = F_electric

where:
m is the mass of the object, and
g is the acceleration due to gravity (approximately 9.8 m/s² on Earth).

Rearranging the equation to solve for mass:

m = F_electric / g

Substitute the value of the electric force calculated in part A and the acceleration due to gravity to find the mass of the object.