Algebra 2

solve the equation -3 cos t = 1 in the interval from 0 to 2p?

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  1. -3 cos t = 1
    cos(t)=-(1/3)

    Look at the plot of cos(t) between 0 and 2π, and note that there are two solutions between π/2 and 3π/2 where cos(t) is negative.

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  2. 1. function g(x)=-x^2-3x+7 . Find the area under the curve for the domain –4£ x £ 1.
    a 71.6 square units
    b. 46 square units
    c.35.83 square units
    d.17.916square units

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  3. ∫-x^2-3x+7dx between -4 and 1
    to evaluate
    [-x³/3-(3/2)x²+7x] between -4 and 1.

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