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physics

A body oscillates with simple harmonic motion along the x-axis. Its displacement varies with time according to the equation x=5 sin (PIE + PIE/3). The velocity (in m/s) of the body at t=1 second is:

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  1. There's probably a typo, you probably meant to post
    x(t)=5 sin (π + πt/3)
    The velocity is the derivative of x with respect to time, giving:
    velocity=x'(t)=5(π/3)cos(π+πt/3)
    Substitute t=1 in x'(t) to get the velocity at t=1.

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  2. The original problem asked for the velocity at t= 1s of the position x(t)= 5sin(pt + p/3).
    Take the derivative of the position function dx(t) = v(t) = 5pCos(p + p/3)

    v(t) = -5*p*Cos(p + p/3)

    v(t) = -7.9

    The negative sign is part of the equation for the angular frequency of the velocity of the body.

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  3. lol

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