# algebra

The perimeter of a rectangle garden is 80m oits length is 4m more than 5 times its width, find the dimensions of the garden

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1. 2W + 2L = 80
L = 5W + 4

Solve for length L and width W.

Using substitution,

2W + 2(5W +4) = 80
12 W = 72
W = 6
L = 34

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