A sled rests at the top of a 25 degree slope that is 80m in length. If uk = .25 and the velocity at the bottom of the incline is 20m/s then what is the weight of the sled?

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  1. Potential energy loss going down = M*g*80 sin 25 = 331.3 M

    Kinetic energy acquired going down = (1/2) M*(Vfinal)^2 = 200.0 M

    Work done against friction going down =
    M*g*cos25*80*uk = 177.6 M

    The first number must equal the sum of the last two numbers. There is no value of mass M that works.

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