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need to find: lim as x > 0 of 4(e^2x  1) / (e^x 1) Try splitting the limit for the numerator and denominator lim lim x>0 4(e^2x1) (4)x>0 (e^2x1) ______________ = ________________ lim lim x>0 e^X1 x>0 e^x1 Next solve for
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Calculus
Find the following limits algebraically or explain why they don’t exist. lim x>0 sin5x/2x lim x>0 1cosx/x lim x>7 x7/x7 lim x>7 (/x+2)3/x7 lim h>0 (2+h)^38/h lim t>0 1/t  1/t^2+t
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Find the limit of the sequence 2ln(1+3n)  ln(4+n^2) What I did: lim as n approach inf of an = 2*lim ln (1+3n)/(4+n^2) = 2 * lim ln (1/n^2 + 3n/n^2) / (4/n^2 + n^2/n^2) = 2 * lim ln (1/n^2 + 3/n) / (4/n^2 + 1) = 2 * lim ln
asked by Helloo on April 25, 2019 
calc
Are these correct? lim x>0 (x)/(sqrt(x^2+4)  2) I get 4/0= +/ infinity so lim x>0+ = + infinity? and lim x>0 = + infinity? lim x>1 (x^2  5x + 6)/(x^2  3x + 2) I get 2/0, so lim x> 1+ =  infinity? and lim x>1 = +
asked by Chelsea on October 13, 2010 
Calc Please Help
Are these correct? lim x>0 (x)/(sqrt(x^2+4)  2) I get 4/0= +/ infinity so lim x>0+ = + infinity? and lim x>0 = + infinity? lim x>1 (x^2  5x + 6)/(x^2  3x + 2) I get 2/0, so lim x> 1+ =  infinity? and lim x>1 = +
asked by Chelsea on October 14, 2010 
Calc. Limits
Are these correct? lim x>0 (x)/(sqrt(x^2+4)  2) I get 4/0= +/ infinity so lim x>0+ = + infinity? and lim x>0 = + infinity? lim x>1 (x^2  5x + 6)/(x^2  3x + 2) I get 2/0, so lim x> 1+ =  infinity? and lim x>1 = +
asked by Chelsea on October 13, 2010 
Calculus
Find the indicated limits. If the limit does not exist, so state, or use the symbol + ∞ or  ∞. f(x) = { 2  x if x ≤ 3 { 1 + 3x  x^2 if x > 3 a) lim 3+ f(x) x>3 b) lim 3 f(x) x>3 c) lim f(x) x>3 d) lim ∞ f(x) x>3
asked by Chris on October 9, 2011 
Calculus
Find the indicated limits. If the limit does not exist, so state, or use the symbol + ∞ or  ∞. f(x) = { 2  x if x ≤ 3 { 1 + 3x  x^2 if x > 3 a) lim 3+ f(x) x>3 b) lim 3 f(x) x>3 c) lim f(x) x>3 d) lim ∞ f(x) x>3
asked by Blue on October 8, 2011 
Calculus
Find the limit. lim 5x/(x^225) x>5 Here is the work I have so far: lim 5x/(x^225) = lim 5x/(x5)(x+5) x>5 x>5 lim (1/x+5) = lim 1/10 x>5 x>5 I just wanted to double check with someone and see if the answer is
asked by S on January 22, 2014 
Calculus
uu) lim ln(1x) as x>1 yy) lim (√(6x)2)/(√(3x)1) as x> 2 zz) lim (1(1/2)arctanx) as x>∞ bbb) lim ln1x as x>1 If these are hard to interpret with all the parentheses, you can plug them in to Wolfram Alpha and it
asked by Emily on February 7, 2012