A Football player on team a is movin gat a velocity of 8ms at an angle of 49 below the x axis. He collides with a player on team B, The Player B is moving at 7.5ms at an angle of 41 below the X and has a mass of 110KG after the collision both players remain in contact and move along the horizontal. what is the mass of player A.

Question

A Football player on team a is movin gat a velocity of 8ms at an angle of 49 below the x axis. He collides with a player on team B, The Player B is moving at 7.5ms at an angle of 41 below the X and has a mass of 110KG after the collision both players remain in contact and move along the horizontal. what is the mass of player A.

so far i have M1 = M2= 110 V1=8 V2=7.5 V1'= V2'

Im not to sure about how to solve this one ?

Answer 1

I believe that you have mistake in given data: velocity of one of the players has to be ABOVE the x-axis. Assume that it is velocity of the player B. Now, y-projection of the law of conservation of linear momentuim gives

- m1•v1•cosα1+ m2•v2•cosαα2=0.
m1= m2•v2•cosαα2/ v1•cosα1 =110•7.5•sin41/8•sin49= 89.7 kg

Answer 2

Thanks alot, I guess my workbook does have a error as it clearly states both as below the horizontal.!

Answer 3

To solve this problem, we can use the principle of conservation of momentum. According to this principle, the total momentum before the collision should be equal to the total momentum after the collision.

Let's consider the horizontal and vertical components of the velocities for both players.

Player A:
Velocity (Va) = 8 m/s
Angle (θa) = 49° below the x-axis

Player B:
Velocity (Vb) = 7.5 m/s
Angle (θb) = 41° below the x-axis

To find the horizontal and vertical components of the velocities, we can use trigonometry.

Horizontal component of Va (Vax) = Va * cos(θa)
Vertical component of Va (Vay) = Va * sin(θa)

Similarly, we can find the horizontal and vertical components of Vb:

Horizontal component of Vb (Vbx) = Vb * cos(θb)
Vertical component of Vb (Vby) = Vb * sin(θb)

After the collision, the players move along the horizontal, implying that their vertical components cancel each other out.

Let's denote the final velocity of both players as Vf.

Therefore, Vay + Vby = 0

Now, let's consider the principle of conservation of momentum:

Mass of player A (Ma) = Mass of player B (Mb) = 110 kg (given)

Momentum before collision (P1) = Momentum after collision (P2)

P1 = (Ma * Va) + (Mb * Vb)
P2 = (Ma * Vf) + (Mb * Vf)

Setting P1 = P2:

(Ma * Va) + (Mb * Vb) = (Ma + Mb) * Vf

Substituting the values and solving for Vf:

(110 * 8 * cos(49°)) + (110 * 7.5 * cos(41°)) = (110 + 110) * Vf

Now, we can calculate the mass of player A (Ma):

Ma = (110 * 8 * cos(49°)) + (110 * 7.5 * cos(41°)) / ((110 + 110) * Vf)

Please solve the equation to find the value of Ma.