A 11.3 kg cart slides down a rough, inclined ramp, angled 24o with respect to the horizontal. At time t = 0 s, the velocity of the cart is 2.75 m/s directed down the ramp. At time t = 0.36 s, the velocity of the cart is 4.16 m/s directed down the ramp. What is the magnitude of the impulse that the cart experiences?

Question

A 11.3 kg cart slides down a rough, inclined ramp, angled 24o with respect to the horizontal.  At time t = 0 s, the velocity of the cart is 2.75 m/s directed down the ramp.  At time t = 0.36 s, the velocity of the cart is 4.16 m/s directed down the ramp.  What is the magnitude of the impulse that the cart experiences?

Elena · Answer

impulse = change in momentum = =mass[ V(final) - V(initial)]= =11.3 (4.16-2.75)=15.93 N•s