a canoe displaces 100 L of water weighs 9.8 NL what is the bouyant force on the canoe
Vw = 100L * 1000cm^3/L=100,000cm^3=Vol. of water displaced.
Dw = 0.001kg/cm^3. = Density of water.
The Buoyant force(Fb) = the wt. of the water displaced:
Fb = Vw * Dw
Fb=100000cm^3 * 0.001kg/cm^3 * 9.8N/kg=
980 N.
980
A canoe displaces 100 L of water. Water weighs 9.8 N/L. What is the buoyant force on the canoe?
To determine the buoyant force on the canoe, we need to use Archimedes' principle. According to this principle, the buoyant force on an object submerged in a fluid is equal to the weight of the fluid displaced by the object.
In this case, the canoe displaces 100 L of water. However, we need to convert the units to match the weight of the water. Since 1 L of water weighs 1 kg, 100 L of water would weigh 100 kg.
Next, we need to convert the weight of the water from kg to Newtons (N). We know that 1 kg is equivalent to 9.8 N (due to the acceleration due to gravity).
Therefore, the weight of the water displaced by the canoe is 100 kg * 9.8 N/kg = 980 N.
Hence, the buoyant force on the canoe is 980 N.