Find the product:
(8x-3y)^2
(8x-3y)^2
=(8x-3y)(8x-3y)
= 64x^2 - 48xy + 9y^2
To find the product of (8x-3y)^2, we need to square the entire expression. Squaring involves multiplying the expression by itself.
(8x-3y)^2 = (8x-3y)(8x-3y)
To simplify this expression, we can use the FOIL method, which stands for First, Outer, Inner, Last.
First: Multiply the first terms of each binomial.
(8x)(8x) = 64x^2
Outer: Multiply the outer terms of each binomial.
(8x)(-3y) = -24xy
Inner: Multiply the inner terms of each binomial.
(-3y)(8x) = -24xy
Last: Multiply the last terms of each binomial.
(-3y)(-3y) = 9y^2
Putting it all together:
(8x-3y)(8x-3y) = 64x^2 - 24xy - 24xy + 9y^2
Combining like terms:
= 64x^2 - 48xy + 9y^2
Therefore, the product of (8x-3y)^2 is 64x^2 - 48xy + 9y^2.