A)What is the equation for equivalent resistance for resistors wired in series? What about series wiring makes resistors in series add the way they do?

B)What is the equation for capacitors wired in parallel? What about parallel wiring makes capacitors add the way they do?

I know what the equations are for both, but I'm not sure why they are that. For B, I think it might have something to do with the charge of a capacitor being directly proportional to the capacitance, but I don't really know. And for A, I don't have any ideas.

A) add the resistance if in series.

The electricity has to squeeze through one then the next.

B) Capacitance is charge per unit voltage. In parallel each holds charge while both have the same total voltage so there is more charge stored per volts so the capacitances add.

A) The equation for equivalent resistance when resistors are wired in series is simply the sum of the resistance values of each individual resistor. Mathematically, it can be represented as:

Req = R1 + R2 + R3 + ... + Rn

In series wiring, resistors are connected end-to-end, such that the current flowing through them is the same. This is due to the fact that there is only one path for the current to flow. The voltage across each resistor adds up, as the total voltage in the circuit is divided among the resistors. This results in the cumulative effect of the resistors, where the total resistance is higher due to the added resistance of each individual resistor along the path.

B) The equation for equivalent capacitance when capacitors are wired in parallel is the sum of the capacitance values of each individual capacitor. Mathematically, it can be represented as:

Ceq = C1 + C2 + C3 + ... + Cn

In parallel wiring, capacitors are connected side-by-side, with both terminals of each capacitor connected to the same pair of nodes. This arrangement allows each capacitor to have the same potential difference or voltage across its terminals. The individual charges on each capacitor add up, as they are connected to the same nodes and thus experience the same voltage. This results in an increase in the total charge stored in the combination of capacitors, which is directly proportional to the equivalent capacitance.